Increases in snow levels are recorded with positive numbers. Decreases in snow levels are recorded with negative numbers. After a winter storm, the depth of the snow on Cherry Street was 10 \text{ cm}10 cm10, start text, space, c, m, end text. But then, the snow started melting at a rate of \dfrac{1}{3} \text{ cm} 3 1 ​ cmstart fraction, 1, divided by, 3, end fraction, start text, space, c, m, end text per hour. What was the depth of the snow on Cherry Street after 333 hours?

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Question:

Increases in snow levels are recorded with positive numbers. Decreases in snow levels are recorded with negative numbers.

After a winter storm, the depth of the snow on Cherry Street was

10 cm. But then, the snow started melting at a rate of 1/3 cm

per hour.

What was the depth of the snow on Cherry Street after 3

hours?

Answer:

The depth of the snow on Cherry Street after 3 hours is 9 cm

Step-by-step explanation:

Here we have

Initial depth of snow = 10 cm

Rate at which the snow melts  = 1/3 cm/hour

Decrease in depth of snow after 3 hours = 3 hour × 1/3 cm/hour = 1 cm

Since decrease in the depth of snow is recorded with negative number, we have;

The decrease in depth of snow after 3 hours = -1 cm

Therefore the depth of the snow after 3 hours is given by;

Depth of snow + change in snow level after 3 hours

= Depth of snow + Decrease in depth of snow after 3 hours (-1)

(Initial depth of snow - Level of snow melted in 3 hours)

= 10 cm - 1 cm = 9 cm

Which gives the depth of snow after 3 hours = 9 cm.

The depth of snow is an illustration of a linear function

The depth of snow after 3 hours is 9cm

The given parameters are:

[tex]Initial = 10cm[/tex]

[tex]Rate = -\frac 13cm/hr[/tex] --- it is negative because the amount of snow decreases with time.

The equation that represents the amount of snow in time (t) is:

[tex]f(t) = Initial + Rate \times t[/tex]

So, we have:

[tex]f(t) = 10 -\frac 13\times t[/tex]

[tex]f(t) = 10 -\frac 13t[/tex]

After 3 hours, the value of t is 3.

So, the equation becomes

[tex]f(3) = 10 -\frac 13 \times 3[/tex]

[tex]f(3) = 10 -1[/tex]

[tex]f(3) = 9[/tex]

Hence, the depth of snow after three hours is 9cm

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