Question

(a) A loop of wire carries a conventional current of 0.3 amperes. The radius of the loop is 0.09 m. Calculate the magnitude of the magnetic field at a distance of 0.33 m along the axis of the loop, from the center of the loop. B

Answer 1

Answer: B = 3.798 ×10^-8 T

Explanation: The magnetic field of a current carrying loop is given by the formulae below.

B =u×I×a²/2(x²+a²) ^3/2

Where B = strength of magnetic field

x = distance of the point the magnetic field is to the center of the loop= 0.33m

a = radius of loop = 0.09m

I = current on the loop = 0.3A

u = permeability of free space = 1.25×10^-6.m kgs^-2A^-2

By substituting all the parameters, we have that

B = 1.25×10^-6 × 0.3 × 0.09²/ 2(0.33²+0.09²)^3/2

B = 3.04×10^-9/ 8.004×10^-2

B= 0.3798 × 10^-7

B = 3.798 ×10^-8 T