Answer: The amount of tetracycline needed for 880 kg of polar bear is 22. grams
Explanation:
We are given:
Effective dose of tetracycline needed = 25 mg/kg = 0.025 g/kg (Conversion factor: 1 g = 1000 mg)
Mass of the polar bear = 880 kg
Applying unitary method:
For 1 kg of mass, the amount of tetracycline needed is 0.025 grams
So, for 880 kg of mass, the amount of tetracycline needed will be = [tex]\frac{0.025g}{1kg}\times 880kg=22.g[/tex]
Hence, the amount of tetracycline needed for 880 kg of polar bear is 22. grams