Question

Andrew solves 6x^2 = 12x by using the quadratic formula. What values does he use for a,b, and c?

Answer 1

Answer:

a = 6, b = -12, c = 0

Step-by-step explanation:

General form of a quadratic equation is:

ax² + bx + c = 0

6x² = 12x

6x² - 12x = 0

6x² - 12x + 0 = 0

(no constant means it's 0)

Comparing to the general form:

a = 6, b = -12, c = 0

Answer 2

The value of a = 6, b = -12, c = 0

• The calculation is as follows:

we know that

The general form of a quadratic equation is:

$ax^2 + bx + c = 0$

$6x^2 = 12x\\\\6x^2 - 12x = 0\\\\6x^2 - 12x + 0 = 0$

Here no constant means it's 0

So,

a = 6, b = -12, c = 0

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