Question

to the opposite figure if you removed one cube from them,
the pressure due to the cubes on the area of contact of the surface
under them will -----
a increase to the double.
Ĉ remain constant.
b decrease to the half.
(d be indeterminable.​

Answer 1

The pressure is the ratio between the force and the area the force is excerted on.

Assuming that the two cubes are identical, they have the same surface area S, and the same weight force F.

So, at the beginning, you have a force of 2F over an area of 2S.

After you remove one cube, you have a force of F over an area of S.

The pressure doesn't change:

$\dfrac{2F}{2S}=\dfrac{F}{S}$