Question

find the surface area of a cylinder to the nearest tenth of a square unit use 3.14 for pi radius is 4.9ft h is 7.8ft

38.2
65.4
286.2
390.8

Answer 1

The surface area of a cylinder to the nearest tenth is 390.8 square feet

Solution:

The surface area of cylinder is given as:

$A=2 \pi rh+2 \pi r^2$

Where, r is the radius and h is the height

From given,

r = 4.9 feet

h = 7.8 feet

Substituting the values we get,

$A = 2 \times 3.14 \times 4.9 \times 7.8 + 2 \times 3.14 \times 4.9^2\\\\A = 240.0216+150.7828\\\\A = 390.8044 \approx 390.8$

Thus the surface area of a cylinder to the nearest tenth is 390.8 square feet