A 26.0 kg kg crate is initially moving with a velocity that has magnitude 3.75 m/s m/s in a direction 37.0 ∘ ∘ west of north. 1. How much work must be done on the crate to change its velocity to 5.31 m/s m/s in a direction 63.0 ∘ ∘ south of east? 2. Express your answer to three significant figures and include the appropriate unit.

Respuesta :

Answer:

184 J

Explanation:

We are given that

Mass of crate=26 kg

Initial velocity=u=3.75 m/s

Direction=[tex]\theta=37^{\circ}[/tex] W of N

Final velocity=v=5.31 m/s

Direction=[tex]63^{\circ}[/tex]S of E

We have to find the work done on the crate to change its velocity.

By using work energy theorem

Work done=Change in kinetic energy

Work done=[tex]\frac{1}{2}mv^2-\frac{1}{2}mu^2[/tex]

Work done=[tex]\frac{1}{2}(26)(5.31)^2-\frac{1}{2}(26)(3.75)^2[/tex]

Work done=367 J-183 J=184 J

ACCESS MORE