Question

An uniform electric field of magnitude E = 100 N/C is oriented along the positive y-axis. What is the magnitude of the flux of this field through a square of surface area A = 2 m2 oriented parallel to the yz-plane?

Answer 1

Answer:

The magnitude of the flux of electric field through a square of surface area is zero.

Explanation:

$E=100 NC^{-1}\\\\A=2 m^2\\\\Electic\,\,flux\,\,flux\,\,is\,\,given\,\,as:\\\\\phi_E=E.A\,cos\,\theta$

It is given that square box is parallel to yz-plane which has normal vector perpendicular to plane in x-direction. Angle between normal vector of area and electric field is 90°. Substituting in (1)

$\phi_E=E.A\,cos\,(90^o)\\\\\phi_E=0$

Answer 2

The magnitude of the flux of electric field through a square of the surface area is zero.

Calculation of the magnitude:

Since

An uniform electric field of magnitude E = 100 N/C is oriented along the positive y-axis.

And,

Area = 2m^2

So, the electric flux should be

= E.Acos\theta

= E.A cos 90 degrees

= 0

Also, It is mentioned that the square box should be parallel to yz-plane that contains normal vector perpendicular to plane in x-direction. And, the Angle between normal vector of the area and an electric field should be 90°.

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