Question

Suppose you are determining the velocity of a baseball by measuring the distance it travels, X, in a time T. You measure X to be 32.5 m ± 0.5 m, and you measure T to be 10 seconds. Assume that T is known "exactly", i.e. the error in T is so small that it can be neglected. Compute the velocity V = X/T, and also compute ζV, the uncertainty in V.

Answer 1

Answer:

V = 3.25 m/s ζV= ±0.02

Explanation:

V=32.5/10 =3.25

ζV= (error/measurement(X))-(error/measurement(T))

=0.5/32.5 -0/10=0.015≈ ±0.02 to be at the same decimal places as the calculated value (V=3.250±0.015 m/s)