Logarithms are powers of the base of the logs. If we consider logs to base 10, we find:[tex] log_{10} 1=0[/tex]
This is because
[tex]10^{0}=1[/tex]
Similarly for natural logs, where the base is the exponential number e, we have
[tex]e^{0}=1[/tex]
This ensures that we have no problems with expressions such as the following:
[tex]ln\ (\frac{60}{1})=ln\ 60-ln\ 1=ln\ 60-0=ln\ 60[/tex]
