Answer:
a.[tex]9.42\times 10^{11} m[/tex]
b.29.9 Km/s
Explanation:
We are given that
The distance between the Sun and the Earth=1 AU=150 million=[tex]150\times 10^9 m=1.5\times 10^{11}[/tex]m
1 million km=[tex]10^9 m[/tex]
Time=365 days
a.Radius=r=[tex]1.5\times 10^{11} m[/tex]
The distance traveled by Earth in in 1 year=[tex]2\pi r=2\times 3.14\times 1.5\times 10^{11}=9.42\times 10^{11} m[/tex]
By using [tex]\pi=3.14[/tex]
The distance traveled by Earth in in 1 year=[tex]9.42\times 10^{11} m[/tex]
b.The distance traveled by Earth in in 1 year (365 days)=1 revolution=[tex]9.42\times 10^{11} m=9.42\times 10^{11}\times 10^{-3}Km=9.42\times 10^8 km[/tex]
1 km=1000 m
Time =365 days=[tex]365\times 24\times 60\times 60=31536000 s[/tex]
1 day=24 hours
1 hour=60 minutes
1 minute=60 seconds
Speed=[tex]\frac{distance}{time}[/tex]
Using the formula
Speed of Earth=[tex]\frac{9.42\times 10^8}{31536000}=29.9 km/s[/tex]
Hence, the speed of Earth=29.9 km/s