Question

what is the equation for​

Answer 1

The equation of a line that is perpendicular to the given line is y = –4x – 16.

Solution:

The equation of a line given is y = 0.25x – 7

Slope of the given line($m_1$) = 0.25

Let $m_2$ be the slope of the perpendicular line.

Passes through the point (–6, 8).

If two lines are perpendicular then the product of the slopes equal to –1.

$\Rightarrow m_1 \cdot m_2=-1$

$\Rightarrow 0.25\cdot m_2=-1$

$\Rightarrow m_2=\frac{-1}{0.25}$

$\Rightarrow m_2=-4$

Point-slope intercept formula:

$y-y_1=m(x-x_1)$

$x_1=-6, y_1=8$ and $m=-4$

Substitute these in the formula, we get

$y-8=-4(x-(-6))$

$y-8=-4(x+6)$

$y-8=-4x-24$

Add 8 on both sides of the equation.

$y-8+8=-4x-24+8$

$y=-4x-16$

Hence the equation of a line that is perpendicular to the given line is

y = –4x – 16