Period is 1
Solution:
Given that,
For the simple harmonic motion equation:
[tex]d = 5\ sin(2 \pi t)[/tex]
To find: Period
Use the following form to find the period
[tex]y = a\ sin(bx-c) + d[/tex]
Where,
a is the amplitude
c is phase shift
d is vertical shift
The period is given as:
[tex]Period = \frac{2 \pi}{b}[/tex]
On comparing,
[tex]y = a\ sin(bx-c) + d\\\\d = 5\ sin(2 \pi t)[/tex]
Thus on comparing we get,
[tex]b = 2 \pi[/tex]
Thus,
[tex]Period = \frac{2 \pi}{b}\\\\Period = \frac{2 \pi }{2 \pi}\\\\Period = 1[/tex]
Thus period is 1
