What is the slope of the line represented by the equation y = –y equals negative StartFraction one-half EndFraction x plus StartFraction one-fourth EndFraction.x + StartFraction one-fourth EndFraction.?

–negative StartFraction one-half EndFraction.
–negative StartFraction one-fourth EndFraction.
StartFraction one-fourth EndFraction.
StartFraction one-half EndFraction.

Respuesta :

Answer:

The slope of the line is -1/2

Explanation:

The general equation of a line is

[tex]y=mx+q[/tex]

where

m is the slope of the line, which is the rate of change of the y-variable with respect to the x-variable

q is the y-intercept, which is the y-coordinate at which the line touches the y-axis

The equation of the line given in this problem is

[tex]y=-\frac{1}{2}x+\frac{1}{4}[/tex]

Therefore, by comparing it with the general equation, we observe that:

[tex]m=-\frac{1}{2}\\q=\frac{1}{4}[/tex]

Therefore, the slope of this line is -1/2.

The slope of the line represented by the equation y = -1/2x + 1/4 is 1/2

The equation of a line

Equation of a line is given by

y = mx + c

where,

  • m = slope of the line
  • c = y-intercept

Given:

y equals negative StartFraction one-half EndFraction x plus StartFraction one-fourth EndFraction

y = -1/2x + 1/4

So,

The slope of the line = 1/2

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