Respuesta :

Answer:

The term to add is

[tex]-\frac{1}{3} x[/tex]

Step-by-step explanation:

Let

b ----> the term to add

we have

[tex]\frac{5}{6}x-4+b=\frac{1}{2} x-4[/tex]

Solve for b

Adds 4 both sides

[tex]\frac{5}{6}x+b=\frac{1}{2} x[/tex]

subtract 5/6x both sides

[tex]b=\frac{1}{2} x-\frac{5}{6}x[/tex]

Remember that

[tex]\frac{1}{2}=\frac{3}{6}[/tex]

substitute

[tex]b=\frac{3}{6} x-\frac{5}{6}x[/tex]

[tex]b=-\frac{2}{6} x[/tex]

Simplify

[tex]b=-\frac{1}{3} x[/tex]

therefore

The term to add is

[tex]-\frac{1}{3} x[/tex]

Answer:

A

Step-by-step explanation:

ACCESS MORE