Answer:
1/2
Explanation:
The woman is a carrier. she must have obtained the X-linked recessive allele from the father XCY.(assuming C stands for color blindness)Therefore she carries the X-linked gene for color blindness on one of her X -chromosomes as a carrier. (XCX), or (XXC)
if she is now crossed with the husband with normal vision;
then ; XY vs XX
the sex and inheritance of the colorblindness is as follows
XCX- carrier girl
XX- normal girl
XCY or XY. or vice-versa (depending on which of the X chromosomes carries the C allele)
The probability depends on the sex of the child. The first child can be a boy or a girl. Assuming the first child is a boy then it can be either of the two boys so 1/2. The girls can not be colorblind because the father who should give the colorblindness X -chromosomes for XX sex-chromosomes is normal . Therefore their probability is not relevant here.