Question

As phosphate is mined, it moves along a conveyor belt, falling off of the end of the
belt into the shape of a right circular cone, as shown.
15.3 feet
48.6 feet
A shorter conveyor belt also has phosphate falling off of the end into the shape of a
right circular cone. The height of the second pile of phosphate is 3.6 feet shorter
than the height of the first. The volume of both piles is the same.
To the nearest tenth of a foot, what is the diameter of the second pile of phosphate?

Answer 1

Answer:

55.6

Step-by-step explanation:

Answer 2

The diameter of the second pile of phosphate is 55.56 feet if the eight of the second pile of phosphate is 3.6 feet shorter than the height of the first.  

What is a cone?

It is defined as the three-dimensional shape in which the base is a circular shape and if we go from circular base to top the diameter of the circle reduces and at the vertex, it becomes almost zero.

Let's suppose the radius of the second pile is r feet:

Then we can frame an equation:

$\rm \dfrac{1}{3}\pi r^2(15.3-3.6)= \dfrac{1}{3}\pi (\dfrac{48.6}{2})^2\times 15.3$

After solving the above expression:

r = 27.79 feet

Diameter = twice the radius = 2(27.79) = 55.58 ≈ 55.56 feet

Thus, the diameter of the second pile of phosphate is 55.56 feet if the eight of the second pile of phosphate is 3.6 feet shorter than the height of the first.

Learn more about the cone here:

brainly.com/question/16394302

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