pls help thx

A bag contains 1 red, 2 blue, and 3 green marbles. Two marbles are drawn from the bag without replacement.

Based on the tree diagram, what is the probability that a GREEN marble and then a RED marble is drawn? (in simplest fraction form)
A)
1
5
B)
1
10
C)
3
10
D)
4
11

so you have 1 red, 2 blue, and 3 red. Together that would be 6 marbles. However it apears that with each draw you gain two marbles. therefore there are 12 possibilities. The likely hood that you will get a green marble then a red marble should be 2/12. In simplified form it is 1/6.

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jaheimolivieri2006 jaheimolivieri2006 · Answer 2 · 2020-04-08T17:15:51+02:00

jaheimolivieri2006 jaheimolivieri2006

08-04-2020

Answer:the answer is 1/5 the other guy got it wrong

Step-by-step explanation:

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pls help thx A bag contains 1 red, 2 blue, and 3 green marbles. Two marbles are drawn from the bag without replacement. Based on the tree diagram, what is the probability that a GREEN marble and then a RED marble is drawn? (in simplest fraction form) A) 1 5 B) 1 10 C) 3 10 D) 4 11

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pls help thx

A bag contains 1 red, 2 blue, and 3 green marbles. Two marbles are drawn from the bag without replacement.

Based on the tree diagram, what is the probability that a GREEN marble and then a RED marble is drawn? (in simplest fraction form)
A)
1
5
B)
1
10
C)
3
10
D)
4
11