Question

Consider the terms in the sequence: {1/3,1/9,1/27,…}

Common ratio of the sequence:
First term in the sequence:
recursive rule that describes the sequence:

Answer 1

Answer:

1/3, 1/3, a×[r^(n-1)]

Step-by-step explanation:

First term is 1/3

Common ratio is the ratio of any two consecutive terms:

Term2/Term1 = (1/9)÷(1/3)

= (1/9)×(3/1)

= 1/3

Let a be the first term and r be the common ratio,

Then any term of the sequence can be obtained using the following formula:

a×[r^(n-1)]