You leave the doctor's office after your annual checkup and recall that you weighed 688 N in her office. You then get into an elevator that, conveniently, has a scale. Find the magnitude and direction of the elevator's acceleration if the scale reads

Find the magnitude of the elevator's acceleration if the scale reads 726 N
Find the direction of the elevator's acceleration if the scale reads 726 N
Find the magnitude of the elevator's acceleration if the scale reads 598 N
Find the direction of the elevator's acceleration if the scale reads 598 N

Respuesta :

Answer:

[tex]a=0.5418\ m.s^{-2}[/tex] upwards

[tex]a=1.283\ m.s^{-2}[/tex] downwards

Explanation:

Given:

weight of the person, [tex]w=688\ N[/tex]

So, the mass of the person:

[tex]m=\frac{w}{g}[/tex]

[tex]m=\frac{688}{9.81}[/tex]

[tex]m=70.132\ kg[/tex]

  • Now if the apparent weight in the elevator, [tex]w_a= 726\ N[/tex]

Then the difference between the two weights is :

[tex]\Delta w=w_a-w[/tex]

[tex]\Delta w=726-688[/tex]

[tex]\Delta w=38\ N[/tex] is the force that acts on the body which generates the acceleration.

Now the corresponding acceleration:

[tex]a=\frac{\Delta w}{m}[/tex]

[tex]a=\frac{38}{70.132}[/tex]

[tex]a=0.5418\ m.s^{-2}[/tex] upwards, because the normal reaction that due to the weight of the body is increased here.

  • Now if the apparent weight in the elevator, [tex]w_a= 598\ N[/tex]

Then the difference between the two weights is :

[tex]\Delta w=w-w_a[/tex]

[tex]\Delta w=688-598[/tex]

[tex]\Delta w=90\ N[/tex] is the force that acts on the body which generates the acceleration.

Now the corresponding acceleration:

[tex]a=\frac{\Delta w}{m}[/tex]

[tex]a=\frac{90}{70.132}[/tex]

[tex]a=1.283\ m.s^{-2}[/tex] downwards, because the normal reaction that due to the weight of the body is decreased here.

Answer with Explanation:

We are given that

Weight of person=w=688 N

a.Scale reading=n=726 N

[tex]m=\frac{w}{g}=\frac{688}{9.8} m[/tex]

By using [tex]g=9.8m/s^2[/tex]

Net force=ma=n-w

[tex]a=\frac{n-w}{m}=\frac{726-688}{\frac{688}{9.8}}m/s^2[/tex]

[tex]a=0.54 m/s^2[/tex]

The sign of acceleration(a) is positive.Therefore, the direction of elevator's accelerating is upwards.

b.Scale reading=n=598 N

[tex]a=\frac{598-688}{\frac{688}{9.8}}=-1.28m/s^2[/tex]

[tex]a=-1.28 m/s^2[/tex]

The sign of acceleration(a) is negative.Therefore, the direction of elevator's accelerating is downwards.

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