Question

A cube of mass m 1 = 7.0 kg is sitting on top of a second cube of the same size and mass m 2 = 0.7 kg while both are in free fall. Ignoring any air resistance, what is the magnitude of the normal force with which the bottom cube is acting on the top cube?

Answer 1

Answer:

0 N

Step-by-step explanation:

We are given that

$m_1=7 kg$

$m_2=0.7 kg$

Total mass =$m_1+m_2=7+0.7=7.7 Kg$

We have to find the magnitude of the normal force with which the bottom cube is acting on the top cube.

When both cube are fall freely then

g=$0m/s^2$

Then, the weight=$mg=7.7\times 0=0 N$

The direction of weight is downward.

We know that

Normal force is equal to weight and act in opposite direction of weight.

When the weight is zero N then

The magnitude of the normal force with which the bottom cube is acting on the top cube=0 N