Question

A +0.2 µC charge is in an electric field. What happens if that charge is replaced by a +0.4 µC charge?

Answer 1

Explanation:

It is known that electric field is responsible for creating electric potential. As a result, it depends only on the electric field and not on the magnitude of charge.

So, when a charge is increased by a factor of 2 then electric potential will remain the same. Since, expression to calculate the electric potential is as follows.

                 U = qV

Since, the electric potential is directly proportional to the charge. Hence, when 0.2 $\mu C$ tends to replaced by 0.4 $\mu C$ then charge is increased by a factor of 2. Hence, the electric potential energy is doubled.

Thus, we can conclude that if that charge is replaced by a +0.4 µC charge then electric potential stays the same, but the electric potential energy doubles.

Answer 2

Whenever that charge would be substituted with a +0.4 C charge, this same electric potential remains unchanged, however, the electrostatic potential energies increases.

Electric field

It has been well understood that the electric field is responsible for the generation of electric potential. As nothing more than a consequence, it is determined only by the electric field and not that the amount of the charge.

As a result, whenever a charge is multiplied by two, the overall electric potential remains constant. Since that day, the phrase for calculating electric potential seems to be as follows.

→ U = qV

Thus the response above is correct.

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