Respuesta :
Answer:
64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.
Step-by-step explanation:
Volume of cylinder = V
Radius of cylinder = r = 0.5 m
Height of the cylinder = 5 m
Volume of cylinder = [tex]\pi r^2h[/tex]
[tex]V=3.14\times (0.5 m)^2\times 5 =3.925 m^3[/tex]
Mass of gasoline = m
Density of gasoline = d = [tex]673 kg/m^3[/tex]
[tex]m=d\times V=673 kg/m^3\times 3.925 m^3=2,641.525 kg[/tex]
Work done to pump the gasoline out of the tank W
Acceleration due to gravity = g [tex].8 m/s^2[/tex]
The center of gravity of fuel in fully filled tank will be centre so, the value of h = 2 m + 0.5 m = 2.5 m
[tex]W =m\times g\times h[/tex]
[tex]W=2,641.525 kg\times 9.8 m/s^2\times 2.5 m=64,717.36 J[/tex]
64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.
The 64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.
What is the volume of cylinder?
[tex]Volume of cylinder (V) =\pi r^{2} h[/tex]
We have given that,radius of cylinder = r = 0.5 m
Height of the cylinder = 5 m
[tex]Volume of cylinder (V) =\pi (0.5)^{2} (5)=3.92m^{3}[/tex]
Mass of gasoline = m
[tex]Density of gasoline (d)=673kg/m^{3}[/tex]
[tex]m=d*(V)[/tex]
[tex]m=673kg/m^{3}*3.92m^{3}=2641.52kg[/tex]
Work done to pump the gasoline out of the tank W
[tex]Acceleration due to gravity (g)=9.8m/s^{2}[/tex]
The center of gravity of fuel in fully filled tank will be center so, the value of h = 2 m + 0.5 m = 2.5 m
Formula for work done is,
[tex]W=m*g*h[/tex]
Therefore we get,
[tex]W=2641.52kg*9.8m/s^{2} *2.5m\\\\W=64717.36J[/tex]
Therefore,the 64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.
To learn more about work needed visit:
https://brainly.com/question/25689052
