Explanation:
The centre of mass of a right cone of height, H lies on the axis of symmetry at a distance of H/4 from the base
= 3H/4 from top.
D = 5 + 36/4
= 14 ft from the upper rim
Mass of liquid in the cone = volume × density (ρ)
= ⅓.π.r².h.ρ
= ⅓ × 36 × [10 × (36/40)]² × π × 60.6
= 18505 lbs.
where,
r = radius of the liquid surface.
Workdone required to lift this to the rim
= force * distance
= 18505 * 4.45 × 14
= 1152861.5 N.ft.
B.
4 ft above the rim needs an extra 1152861.5 × 4
= 4611446 N.ft.
Total workdone = 1152861.5 + 4611446
= 5764307.5 J.
