Answer:
The question is incomplete. Below is the complete question
"A fair die is tossed. A is the event that the outcome is odd. B is the event that the outcome is even. C is the event that the outcome is less than 4. Determine P(A), P(B), P(C), P(A∩B), P(B∩C), P(A|B), P(A|C), P(B|C).
answers:
a.1/2
b. 1/2
c. 1/2
d.0
e. 1/6
f. 0
g. 2/3
h. 1/3
Step-by-step explanation:
lets write out the probability of each event
a.A=outcome is odd
A={1,3,5}
P(A)=1/2
b.B=outcome is even
B={2,4,6}
P(B)=1/2
c. C=outcome is less than 4
C={1,2,3}
P(C)=1/2
d.P(AnB)={its odd and even i.e what is common between set A and B}
Therefore, P(AnB) is a null set i.e P(AnB)={ }=0
e. BnC= {2} i.e elements common between set B and C
Hence P(BnC)=1/6
f. P{A|B}= P(AnB)/P(B) since P(AnB)=0, P(B)=1/2. then, P(A|B)=0
g. P(A|C)= P(AnC)/P(C) since P(AnC)=1/3, P(C)=1/2. therefore, P(A|C)=2/3
h. P(B|C)= P(BnC)/P(C), since P(BnC)=1/6, P(C)=1/2. therefore, P(B|C)=1/3