100 kg of R-134a at 280 kPa are contained in a piston-cylinder device whose volume is 8.672 m3. The piston is now moved until the volume is one-half its original size. This is done such that the pressure of the R-134a does not change. Determine the final temperature and the change in the total internal energy of the R-134a. (Round the final answers to two decimal places.)

Respuesta :

Answer:

∆u =-111.8 kJ/kg

T_fin=-10.09℃

Explanation:

note:

solution is attached in word file due to some technical issue in mathematical equation. please find the attached documents.

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