Question

What is the concentration of K+K+ ions in a 0.025 M M K2CO3K2CO3 solution assuming complete dissociation? Express the concentration in molarity.

Answer 1

Answer:

0.05 M

Explanation:

Given that:-

The molarity of $K_2CO_3$ = 0.025 M

$K_2CO_3$ will dissociate according to the reaction shown below:-

$K_2CO_3\rightarrow 2K^++CO_3^{2-}$

According to the above reaction:-

1 mole of $K_2CO_3$ on dissociation forms 2 moles of $K^+$

0.025 mole of $K_2CO_3$ on dissociation forms 2*0.025 moles of $K^+$

So, They are present in same volume.

So, concentration of $K^+$ ions = 0.05 M

Answer 2

Answer:

The molarity of the K+ ions is 0.050 M

Explanation:

Step 1: Data given

Molarity K2CO3 = 0.025 M

Step 2: The equation

K2CO3 ⇒ 2K+ + CO3^2-

Step 3: Calculate the concentration of K+

Concentration = 2*0.025 M = 0.050 M

The molarity of the K+ ions is 0.050 M