Question

What is the magnitude of the average net force required to bring a 1,598 kg car to rest from a speed of 93.9 km/h within a distance of 57.2 m? g

Answer 1

Answer:

F= 9492.12 N

Explanation:

Given that

mass, m = 1598 kg

Initial velocity ,u= 0 km/h

Final velocity v= 93.9 km/h

v =26.08 m/s

Distance ,d= 57.2 m

We know that

v² = u² + 2 a d

a=acceleration

u=initial velocity

v= final velocity

d=distance

26.08²= 0² + 2 x a x 57.2

$a=\dfrac{26.08^2}{2\times 57.2}\ m/s^2$

a= 5.94 m/s²

We know that

Force = mass x acceleration

F= m a

F= 5.94 x 1598 N

F= 9492.12 N