Answer:
The PH of the mixture is 4.74
Explanation:
The number of millimoles of acetic acid is calculated using the formula:
No of millimoles= Molarity * Volume( in ml)
= 0.25M * 30ml = 7.5 moles
Number of millimoles of KOH is calculated using:
Number of millimoles = Molarity * Volume ( in ml)
=0.05M * 75ml
= 3.75 moles
The PH of the solution is derived using:
pH = pKa + log [salt] / acid
= [tex] -log [ 1.8 * 10^5 ] + log [ 3.75 mmoles/ 3.75 mmoles] [/tex]
=4.74
