Answer:
The number of cows and calves Mitchel can transport is determined by the inequity [tex]90g+360c \leq 5000[/tex]
Step-by-step explanation:
Let [tex]g[/tex] be the number of goats, and [tex]c[/tex] be the number of cows. If Mitchel's livestock trailer can only hold maximum of 5000 pounds. then we have the inequality
[tex]90g+360c \leq 5000[/tex] (this says that the weight of the goats and the calves cannot exceed 500 pounds.)
Therefore, this inequality determines the number of goats and calves Mitchel can take in a single trip.