The measure of one of the acute angles of a right triangle is decreasing at the rate of π / 36 rad / sec. If the length of the hypotenuse is a constant 40 cm, how fast is the area changing when the acute angle is π / 6?

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The answer is in the attachment

Ver imagen fahadisahadam

Pythagoras  theorem is applicable only in right angle triangle.

Area will be changing at the rate of  (100/9) π cm²/sec.

Let us consider a right angle triangle have hypotenuse of 40 cm and acute angle is ∅.

So, Base is 40 cos ∅ and perpendicular is 40 sin ∅

Since,  Area = 1/2 (base)(height)

A= 1/2 (40cos ∅)(40sin ∅)

A= 800sin  ∅ cos  ∅

A= 400 (2sin ∅ cos ∅)

A= 400sin 2∅

Differentiate above equation with respect to time.

 dA/dt = 800 cos 2∅ (d∅/dt)

Since, d∅/dt is given π/36 rad/sec

So,  dA/dt at ∅ = π/6

dA/dt = 800(1/2)(π/36)

dA/dt = (100/9)π cm²/sec.

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