Answer: 1) 0.674, 2) 0.659, 3) 0.326.
Step-by-step explanation:
Since we have given that
Shock Resistance High Low Total
Scratch high 71 14 85
Resistance low 16 28 44
Total 87 42 129
A be the event that a disk has high shock resistance
B be the event that a disk has high scratch resistance
1) P(A) is given by
[tex]\dfrac{87}{129}=0.674[/tex]
2) P(B) is given by
[tex]\dfrac{85}{129}=0.659[/tex]
3) P(A') is given by
[tex]P(A')=1-P(A)\\\\P(A')=1-0.674\\\\P(A')=0.326[/tex]
Hence, 1) 0.674, 2) 0.659, 3) 0.326.