Area of the carpet needed = 38 ft²
Solution:
The given image is splitted into two shapes.
One is trapezoid and the other is triangle.
Top base of the trapezoid = 8 ft
Bottom base of the trapezoid = 12 ft
Height of the trapezoid = 3 ft
Area of the trapezoid = [tex]\frac{1}{2} (a+b)\times h[/tex]
[tex]$=\frac{1}{2}(8+12)\times3[/tex]
[tex]$=10\times3[/tex]
= 30
Area of the trapezoid = 30 ft²
Base of the triangle = 12 ft – 8 ft = 4 ft
Height of the triangle = 4 ft
Area of the triangle = [tex]\frac{1}{2} b h[/tex]
[tex]$=\frac{1}{2} \times4\times4[/tex]
= 8
Area of the triangle = 8 ft²
Area of the carpet = Area of the trapezoid + Area of the triangle
= 30 ft² + 8 ft²
= 38 ft²
Area of the carpet = 38 ft²
Hence 38 square feet of outdoor carpet will need for this hole.
