Question

A bicyclist is moving toward a sheer wall while holding a tuning fork rated at 488 Hz. 1) If the bicyclist detects a beat frequency of 8 Hz (between the waves coming directly from the tuning fork and the echo waves coming from the sheer wall), calculate the speed of the bicycle. Assume the speed of sound is 343 m/s.

Answer 1

Answer:

speed of the bicycle = 2.81 m/s

Explanation:

given data

tuning fork rated f = 488 Hz

beat frequency fb = 8 Hz

speed of sound vs = 343 m/s

solution

we get here frequency that rider is listening that is

rider hearing frequency = 488 Hz + 8 Hz

rider hearing frequency = 496 Hz

and when it bouncing from sheer wall at frequency of related to stationary object

frequency = 488 Hz + 4 Hz

frequency =  492 Hz

so now we get speed of the bicycle that is

speed of the bicycle =  (  $\frac{492}{488}$ × 343 )  - 343 Hz

speed of the bicycle = 2.81 m/s

Answer 2

The speed of the bicycle is 2.81 m/s.

Based on the given information,

• The tuning fork rated at frequency (f) 488 Hz.

• The beat frequency (fb) given is 8Hz.  

• The speed of the sound is 343 m/s.  

Now with the help of the given information, the rider is hearing a frequency of,

$=(f+fb)\\=(488+8)\\=496 Hz$

However, it is bounding from sheer wall at the frequency of,

$=(488+\frac{8}{2})\\= 492 Hz$

Now the speed of the bicycle will be,

$=(\frac{492}{488} * 343)-343\\=2.811 m/s\\= 2.81 m/s$

Thus, the speed of the bicycle is 2.81 m/s.

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