Question

If a tensile load of 100 pounds is applied to a rod which has a diameter of 1 inch, what is the stress in the rod?

Answer 1

Answer:

$\sigma=127.32\ pounds/in^2$

Explanation:

Given that

Load ,P = 100 Pounds

Diameter ,d= 1 inch

We know that stress in the rod due to load P is given as

$\sigma=\dfrac{P}{A}$

P=Load

A=Area

Now by putting the values in the above equation, we get

$\sigma=\dfrac{100}{\frac{\pi}{4}\times 1^2}\ Pounds/in^2$

$\sigma=127.32\ pounds/in^2$