Respuesta :

Answer:

See attachment

Step-by-step explanation:

We want to graph the following equation:

x-y+1=0

and

3x+2y=12

For the first equation: x-y+1=0

When x=0, we have 0-y+1=0---->y=1

We plot the point (0,1)

When y=0, we have x-0+1=0---->x=-1

We plot (-1,0)

We draw a straight line through these two points to get the graph of this line.

For the second equation: 3x+2y=12

When x=0,y=6. So we plot (0,6)

When y=0, x=4, So we plot (4,0)

We draw another straight line through them to obtain the graph in the attachment.

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