Question

what value of x is in the solution set of 4x – 12 ≤ 16 8x?

Answer 1

There is an operator missing.

I will assume that the right inequality is 4x - 12 ≤ 16 + 8x

4x - 8x ≤ 16 +12

- 4x ≤ 28

x ≥ - 28/4

x ≥ - 7

Answer 2

we have

$4x-12\leq 16+8x$

The options of the question are

$-10\ -9\ -8\ -7$

Group terms that contain the same variable, and move the constants to the opposite side of the inequality

$-12-16\leq 8x-4x$

$-28\leq 4x$

rewrite the inequality

$4x\geq -28$

Divide by $4$ both sides

$x\geq -7$

The solution is the interval-------> [-7,∞)

All real numbers greater than or equal to $-7$

therefore

the answer is

$-7$