Question

in the following reaction, is sb reduced or oxidized? 2sb (s) 6h2so4 (aq) sb2(so4)3 3so2 6h2o

Answer 1

In the reactants Sb has oxidatin number 0 (because it is in its elemental form)

In the products Sb has oxidaton number +3.

Then Sb lost electrons which means it oxidized.

Answer 2

in the following reaction, Sb is oxidized.
2Sb (s) + 6H2SO4 (as) → Sb2(SO4)3 + 3SO2 + 6H2O