Question

Trapezoid JKLM is shown on the coordinate plane below:

Trapezoid JKLM on the coordinate plane with ordered pairs at J negative 6, 5, at K negative 3, 5, at L negative 1, 2, at M negative 8, 2.

If trapezoid JKLM is translated according to the rule (x, y) → (x + 2, y − 6), what are the coordinates of point L'?

Answer 1

Every point is translated according to the rule ( x, y ) → ( x + 2, y - 6 )
L ( -1, 2 ) → L´ ( -1 + 2,  2 - 6 ) = ( 1, -4 )

Answer 2

Answer:

The Coordinate of point L' is (1,-4)

Step-by-step explanation:

Trapezoid JKLM on the coordinate plane with ordered pairs

J(-6,5)

K(-3,5)

L(-1,2)

M(-8,2)

If trapezoid JKLM is translated according to the rule (x, y) → (x + 2, y − 6)

We need to find the coordinate of L'

L(-1,2)

(x, y) → (x + 2, y − 6)

Rule of translation: x-coordinate shift 2 unit right and y-coordinate shift 6 unit down.

    L → L'

(-1,2) → ( -1+2, 2-6)

(-1,2) → (1,-4)

Hence, The Coordinate of point L' is (1,-4)