Question

The endpoints of EF¯¯¯¯¯ are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of EF¯¯¯¯¯? (xF2,yF2) (xE2,yE2) (xE+xF2,yE+yF2) (xE+xF2,yE+yF2)

Answer 1

The coordinates of the midpoint of EF are: 
M ( $\frac{xE+xF}{2}, \frac{yE+yF}{2}$ )

Answer 2

Answer:  The correct option is (D) $\left(\dfrac{xE+xF}{2},\dfrac{yE+yF}{2}\right).$

Step-by-step explanation:  Given that the co-ordiantes of the end-points of segment EF are E(xE, yE) and F(xF, yF) respectively.

To find the co-ordinates of the mid-point of EF.

We know that

the co-ordinates of the mid-point of a line segment with end-points A(a, b) and B(c, d) are given by

$\left(\dfrac{a+c}{2},\dfrac{b+d}{2}\right).$

Therefore, the co-ordinates of the mid-point of segment Sf will be

$\left(\dfrac{xE+xF}{2},\dfrac{yE+yF}{2}\right).$

Thus, (D) is the correct option.