solomon needs to justify the formula for the arc length of a sector. which expression best completes this argument? the circumference of a circle is given by the formula c=pi * d , where d is the diameter. because the diameter is twice the radius, c= 2 * pi * r. if equally sized central angles, each with a measure of n°, are drawn, the number of sectors that are formed will be equal to 360°/n° the arc length of each sector is the circumference divided by the number of sectors, or _____. therefore, the arc length of a sector of a circle with a central angle of n° is given by 2*pi*r*n/360 or pi*r*n/180 . a. 2*pi*r/270/n b. 2*pi*r/360/n c. 2*pi*r/180/n d. 2*pi*r/90/n

Respuesta :

the numbers of sectors is 360/n

Then, the arc length is the circumference divided by 360/n which is the same that the circumference times n/360

So, the arc length is 2*pi*r/(360/n), which is the option b.

Answer:  The answer is (b). [tex]\dfrac{2\pi r}{\frac{360^\circ}{n^\circ}}.[/tex]


Step-by-step explanation: Let us consider a circle with centre "O" and radius OA=OB=r units. We know that the circumference of a circle is [tex]2\pi\times radius~of~the~circle,[/tex] so the circumference of Circle 'C' is given by

[tex]Circumference=2\pi r.[/tex]

Also, let us central angles of equal size of 'n°', the the number of sectors formed is given by

[tex]no.~of~sectors=\dfrac{360^\circ}{n^\circ}.[/tex]

Now, the formula for arc length of a sector is given by

[tex]arc~length~of~of~a~sector=\dfrac{Circumference~of~the~circle}{no.~of~equally~sized~sectors}.[/tex]

∴ [tex]arc~length~of~of~a~sector=\dfrac{2\pi r}{\frac{360^\circ}{n^\circ}}.[/tex]

Thus, (b) is the correct option.

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