Respuesta :
I assume that the equation is (2x-5)^2 = 11
Taking square root on both sides, that becomes 2x - 5 = (+/-) √11
Then:
2x = (+/-)√11 + 5
x = [5 +/- √11 ] / 2
x = 5/2 +/- (√11)/2
That is, x = 5/2 +(√11)/2 and x = 5/2 - (√11)/2
Taking square root on both sides, that becomes 2x - 5 = (+/-) √11
Then:
2x = (+/-)√11 + 5
x = [5 +/- √11 ] / 2
x = 5/2 +/- (√11)/2
That is, x = 5/2 +(√11)/2 and x = 5/2 - (√11)/2
(2x - 5)² = 11 -- (1)
Square root both sides of (1), i.e.
√(2x - 5)² = ± √11 -- (2)
From (2), we have
2x - 5 = ± √11 -- (3)
By adding 5 to both sides in (3), we have
2x = 5 ± √11 -- (4)
Divide both sides of (4) by 2, and we obtain
x = (5 ± √11)/2 -- (5)
From (5), the solution set of (1) is
x = (5 + √11)/2, (5 - √11)/2 ...Ans.