Respuesta :
c) (6+s) (s2-6s+36)
For sum of cubes you add the first binomial and subtract then add in the following trinomial.
a3+b3=(a+b)(a2-ab+b2)
For sum of cubes you add the first binomial and subtract then add in the following trinomial.
a3+b3=(a+b)(a2-ab+b2)
Answer:
Option 3 is correct that is [tex](6+s)(s^2-6s+36)[/tex]
Step-by-step explanation:
We have general formula for sum of cube which is
[tex]a^3+b^3=(a+b)(a^2+b^2-ab)[/tex]
Here, we have a=s and b=6
on substituting the values in the formula we will get
[tex]6^3+s^3=(6+s)(s^2+6^2-6s)[/tex]
After simplification we will get
[tex]6^3+s^3=(6+s)(s^2+36-6s)[/tex]
After rearranging the terms we will get
[tex]6^3+s^3=(6+s)(s^2-6s+36)[/tex] which exactly matches option 3 in the given options.
Therefore, option 3 is correct that is [tex](6+s)(s^2-6s+36)[/tex]