Question

what is the value of x in the equation 1,331x3 − 216 = 0?

Answer 1

In solving for the value of x in the equation 1331x^3 - 216 = 0, the steps are shown below:

1331x^3 - 216 = 0
(1331x^3 = 216) / 1331
x^3 = 216/1331
x = cube root (216/1331)
x = 6/11

Therefore, the value of x in the equation is 6/11.

Answer 2

Answer:

Value of $x =\frac{6}{11}$

Step-by-step explanation:

Given the equation: $1331x^3 -216 =0$             .....[1]

Addition property of equality states that you add the number to both sides of an equation.

Add 216 to both sides of an equation [1]

$1331x^3 -216+216 =0+216$

Simplify

$1331x^3=216$

As,we know that  $11 \times 11 \times 11 =11^3 = 1331$ and $6 \times 6 \times 6 =6^3 = 216$

then the given equation becomes;$11^3x^3=6^3$

or

$(11x)^3=6^3$                    ......[2]

Using  $a^3=b^3$ then a=b.

[2] ⇒

11x =6

Divide both sides of an equation by 11, we get

$\frac{11x}{11} =\frac{6}{11}$

Simplify:

$x =\frac{6}{11}$

therefore, the value of x is, $\frac{6}{11}$