Question

the hubble telescope’s orbit is 5.6 × 10^5 metersabove earth’s surface. the telescope has a massof 1.1 × 10^4 kilograms. earth exerts a gravitationalforce of 9.1 × 10^4 newtons on the telescope. themagnitude of earth’s gravitational field strengthat this location is(1) 1.5 × 10^−20 n/kg (3) 8.3 n/kg(2) 0.12 n/kg (4) 9.8 n/kg

Answer 1

The gravitational field strength = Defined as Gravitational Force per unit mass

Gravitational Field Strength =

= Gravitational Force Exerted / Mass of object exerted on  

= (9.1*10⁴) / (1.1*10⁴)

= 9.1/1.1

≈ 8.27  N/kg

≈ 8.3 N/kg

Option (3) is the answer.