Question

as light shines from air to water (n = 1.43) at an incident angle of 36.0 º, what is its angle of refraction?

Answer 1

Snell's law:
sin (angle of incidence) / sin (angle of refraction) = n_2/n_1
$\frac{sin\theta_1}{sin\theta_2}=\frac{n_2}{n_1}$
sin 36° / sin Θ = 1.43/1
sin Θ = (sin 36°)/1.43
sin Θ = 0.411
Θ = 24.3°