Question

3=3/4(b-8)
Please help me thank you!

Answer 1

So you need to isolate/get "b" by itself in the equation:

$3=\frac{3}{4}(b-8)$       Distribute/multiply 3/4 into (b - 8)

$3=(\frac{3}{4}(b))+(\frac{3}{4}(-8))$

$3=(\frac{3}{4} b)+(-6)$           Don't know which goes into the parentheses....think the one above makes more sense...maybe....sorry

$3=\frac{3}{4} b-6$           Add 6 on both sides

$9=\frac{3}{4} b$        Multiply the reciprocal of 3/4 to get rid of the fraction and get b by itself, which would be 4/3  [basically flipping the fraction or switching the numerator and the denominator]

$\frac{36}{3} =b$            Simplify the fraction

12 = b