Answer:
mass(g) = 0.55114g
Explanation:
Given that;
Molarity (M) 100mM = 0.1M
Volume (V) = 1mL
= 1.0 × 10⁻³ Litre
numbers of moles = Molarity × Volume
= 0.1M × 1.0 × 10⁻³ L
= 0.001
= 1.0 × 10⁻³ mol
Now, to determine the mass of ATP (in solid form) that we need to weigh;
we have our numbers of moles to be =[tex]\frac{mass(g)}{molarmass(g)}[/tex]
where;
numbers of moles = 1.0 × 10⁻³ mol
molar mass = 551.14
mass(g) = numbers of moles × molar mass
mass(g) = 1.0 × 10⁻³ mol × 551.14
mass(g) = 0.55114g
∴ 0.55114g ATP(in solid form) is required to be weighed in order to make 1 mL of stock solution with a concentration of 100 mM ATP.