Question

Marcos had 15 coins in nickels and quarters. He had 3 more quarters than nickels. He wrote a system of equations to represent this situation, letting x represent the number of nickels and y represent the number of quarters. What is the solution?

Answer 1

Answer:

Marcos had 6 nickel coins and 9 quarter coins.

Step-by-step explanation:

We are given the following in the question:

Let x be the number of nickel coins and y be the number of quarter coins.

Marcos had 15 coins in nickels and quarters.

Thus, we can write the equation:

$x + y =15$

He had 3 more quarters than nickels. We can write he equation,

$y = x + 3$

Solving the two equations, we get,

$2y = 18\\y = 9\\x + 9 = 15\\x = 6$

Thus, Marcos had 6 nickel coins and 9 quarter coins.