Question

I had three probability questions (will give 15 points, 5 for each):

1. Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a green marble, replacing it, and then picking a brown marble?

2. Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a yellow marble, replacing it, and then picking another yellow marble?

3. Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a blue marble, not replacing it, and then picking a brown marble?

Not looking for percentages but rather number of favorable options over number of possible outcomes. Thank you so much! Will award Brainliest.

Answer 1

Answer:

Step-by-step explanation:

total number of  marbles=4+2+5+1+7=19

1.

P=4/19*1/19=4/361

2.

P=5/19*5/19=25/361

3.

P=7/19*1/18=7/342